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    • 领扣:1369. Most Common Word

      1369. Most Common Word

      Given a paragraph and a list of banned words, return the most frequent word that is not in the list of banned words. It is guaranteed there is at least one word that isn't banned, and that the answer is unique.

      Words in the list of banned words are given in lowercase, and free of punctuation. Words in the paragraph are not case sensitive. The answer is in lowercase.

      Example

      Example1

      Input:  paragraph = "Bob hit a ball, the hit BALL flew far after it was hit." and banned = ["hit"]
      Output: "ball"
      Explanation:
      "hit" occurs 3 times, but it is a banned word.
      "ball" occurs twice (and no other word does), so it is the most frequent non-banned word in the paragraph. 
      Note that words in the paragraph are not case sensitive,
      that punctuation is ignored (even if adjacent to words, such as "ball,"), 
      and that "hit" isn't the answer even though it occurs more because it is banned.

      Example2

      Input:  paragraph = "a a a b b c c d" and banned = ["a","b"]
      Output: "c"
      Explanation:
      "a" and "b" are banned words
      "c" occurs 2 times and "d" occurs only once
      So output "c"

      Notice

      • 1 <= paragraph.length <= 1000.

      • 1 <= banned.length <= 100.

      • 1 <= banned[i].length <= 10.

      • The answer is unique, and written in lowercase (even if its occurrences in paragraph may have uppercase symbols, and even if it is a proper noun.)

      • paragraph only consists of letters, spaces, or the punctuation symbols !?',;.

      • Different words in paragraph are always separated by a space.

      • There are no hyphens or hyphenated words.

      • Words only consist of letters, never apostrophes or other punctuation symbols.

      import re
      class Solution:
          """
          @param paragraph: 
          @param banned: 
          @return: nothing
          """
          def mostCommonWord(self, paragraph, banned):
              # 
              bandictionary = {}
              resultdictionary = {}
              
              lowpara = paragraph.lower()
              
              para = re.split(r'[!?,;.\s* \']\s*', lowpara)
              
           
              for item in range(len(banned)):
                  bandictionary[banned[item]] = item
              
              result = ''
              for eachitem in para:
                  if eachitem not in bandictionary and eachitem is not '' :
                      if result == '':
                          result = eachitem
                      if resultdictionary.get(eachitem) is None:
                          resultdictionary[eachitem] = 1 
                      else:
                          resultdictionary[eachitem] += 1 
                      itemres = resultdictionary.get(eachitem)
                      #print(itemres)
                      #print(resultdictionary[eachitem])
                      print(resultdictionary)
                      if itemres and int(resultdictionary[eachitem]) >= int(resultdictionary[result]):
                          result=eachitem
              return result

      Using library re to split the words, lower() to convert string to lower case.

      Save words that not in ban-dictionary to result-dictionary, save the highest repeats words to result.

      Return result.

      It will take up to log(n) space complexity, and log(n) time complexity, because we go over the array once.

      纽约州·纽约
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